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OpenStudy (misssmartiez):
OpenStudy (misssmartiez):
Talk me through it and why, please :)!
OpenStudy (faiqraees):
How about I tell you a very short and easy method??
OpenStudy (misssmartiez):
Ok. @FaiqRaees :D
OpenStudy (faiqraees):
Take any value of x (that lies in the domain) and put in the function and note the value of y. Do it with 2,3 more values of x and note down the values for y. Then compare all the graphs and check which one satisfies all the values.
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OpenStudy (faiqraees):
In this question, you can narrow down the answer just by using x = 6 and x =3
OpenStudy (misssmartiez):
Still don't get it ;-:
OpenStudy (faiqraees):
y =1/3|x|-2 y =1/3|x|-2
y = 1/3x|6|-2 y = 1/3 x|3|-2
y = 2-2 y = 1 -2
y = 0 when x =6 y = -1 when x =3
So the correct graph should contain the points (6,0) and (3,-1)
OpenStudy (misssmartiez):
D
OpenStudy (faiqraees):
Perfect so now you get it?
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OpenStudy (misssmartiez):
Looking at the points 6,0 and 3, -1. How did you figure that stuff out?
OpenStudy (faiqraees):
Figure which stuff out?
OpenStudy (misssmartiez):
y =1/3|x|-2 y =1/3|x|-2 y = 1/3x|6|-2 y = 1/3 x|3|-2 y = 2-2 y = 1 -2 y = 0 when x =6 y = -1 when x =3