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Mathematics 17 Online
OpenStudy (misssmartiez):

Attachment :3

OpenStudy (misssmartiez):

OpenStudy (misssmartiez):

Talk me through it and why, please :)!

OpenStudy (faiqraees):

How about I tell you a very short and easy method??

OpenStudy (misssmartiez):

Ok. @FaiqRaees :D

OpenStudy (faiqraees):

Take any value of x (that lies in the domain) and put in the function and note the value of y. Do it with 2,3 more values of x and note down the values for y. Then compare all the graphs and check which one satisfies all the values.

OpenStudy (faiqraees):

In this question, you can narrow down the answer just by using x = 6 and x =3

OpenStudy (misssmartiez):

Still don't get it ;-:

OpenStudy (faiqraees):

y =1/3|x|-2 y =1/3|x|-2 y = 1/3x|6|-2 y = 1/3 x|3|-2 y = 2-2 y = 1 -2 y = 0 when x =6 y = -1 when x =3 So the correct graph should contain the points (6,0) and (3,-1)

OpenStudy (misssmartiez):

D

OpenStudy (faiqraees):

Perfect so now you get it?

OpenStudy (misssmartiez):

Looking at the points 6,0 and 3, -1. How did you figure that stuff out?

OpenStudy (faiqraees):

Figure which stuff out?

OpenStudy (misssmartiez):

y =1/3|x|-2 y =1/3|x|-2 y = 1/3x|6|-2 y = 1/3 x|3|-2 y = 2-2 y = 1 -2 y = 0 when x =6 y = -1 when x =3

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