Question

medal and fan!

Answer 1

x + 2y = −10
3x − y = 12

x − 2y = −10
3x − y = 12

x + 2y = −10
3x + y = 12

x − 2y = −10
3x + y = 12

Answer 2

So you need to find what pair of equations those two are right?

Answer 3

A) x + 2y = −10
3x − y = 12

b) x − 2y = −10
3x − y = 12

C) x + 2y = −10
3x + y = 12

D) x − 2y = −10
3x + y = 12

Answer 4

\[y_{1} = m_{1}(x)+b \]

\[y_{2} = m_{2}(x)+b \]

easy way to do this is to first find out what the y intercept is for each. that's the b value.
so for each equation can you tell me where each one touches the y axis when x is zero?

Answer 5

so look at the graph and tell me at what value the first equation touches the y axis when x = 0 and the same for the second one

Answer 6

0,-5 and 4,0

Answer 7

right?

Answer 8

okay yep so one is 0,-5

so look now what this one becomes

\[y_{1} = (m_{1)}x-5 \]

now we can find the slope

so for that graph we can pick any two points we want

and find the slope of this

(0,-5)
(-2,-4)

do you know how to find the slope?

Answer 9

no not really

Answer 10

we use this formula to find the slope

\[m = \frac{ y_{2}-y_{1} }{ x_{2}-x_{1} }\]

Answer 11

there's probably a faster-way to do this, you could probably just plug in the solution set into each equation. and see if it satisfies both. but I think this way is alright too.

Answer 12

okay give me a sec

Answer 13

im struggling

Answer 14

u wouldnt necessarily need the slope..u could just find the x and y intercepts

Answer 15

so 0,-5 and 4,0

Answer 16

nonononono never mind

Answer 17

2,-6?

Answer 18

x + 2y = -10
2y = - x - 10
y = - 1/2x - 5
so y int is (0,-5)

Answer 19

x int can be found by subbing in 0 for y
x + 2y = - 10
x + 2(0) = - 10
x = - 10

so for 1st eq...x int is (-10,0) and y int is (- 5,0)

Answer 20

now u would need to find x and y intercepts for each answer choice and see what matchesur graph