Help with Algebra 1 math. MEDAL!
Answer key says the answer is D. But I don't know why.
Can you calculate the change in each year?
I think I did. from 1898-1971 diff in years: 73 diff in cost: 5 5/73 = 0.07 from 1971-1985 diff in years: 14 diff in cost: 8 from 1985-2006 diff in years: 21 diff in cost: 10 10/21 = 0.48 from 2006-2012 diff in years: 6 diff in cost: 11 6/11 = 0.55
sorry from 1971-1985 the average rate when doing 8/14 = 0.57
i don't know why it's not 2 but 4. the work that i have shows that 2 is greater than 4
thats hould be 11/6 for last period not 6/11
In all the others youre doing change in year/change in cost. Thats wrong. Do change in cost/change in year
@FaiqRaees I don't understand.
its obviously D .... \[\frac{ 11 }{ 6 } = 1.833333\]
required rate = increase in cost / number of years
For each option apply, Change in cost/ change in year
but when i did A, i got something more than that. @rishavraj
and @FaiqRaees and @welshfella wasn't that what i have been doing?
average rate = \[\frac{ changein cost }{ time }\]
@calculusxy for A its 5/73 which is really less
For a you will get 6-1/73 = 0.07 and, no you were actually doing it but you for d you did change in years/change in cost
oh sorry. i confused it for 73/5
A = 5 / 73 you made a mistake in the last period 2006-2012 You calculated 6/11 instead of 11/6
oh okay
thanks for the help :)
No problem
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