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In circle A shown below, Segment BD is a diameter and the measure of Arc CB is 36°:
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What is the measure of ∠DBC? 36° 72° 18° 54°
@Orange_ Is this one more easy to understand?
as BAD is a diameter m < BCD = 90 degrees Now if you can find m < BDC you can find m <DBC
What do you mean?
i think m< CDB = measure of the given arc
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the 3 angles of a triangle add up to 180 so <BDC = 180 - (90 + < BDC)
126
* correction < DBC = 180 - 990 + < BDC)
180 - 126
54
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yep
Yea - i looked up the relevant theorem about arcs .
We never did those in school. (Many years ago!!!!!)
I'm talking about just after WWII.
Oh wow, thanks though!!!
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