Question

Probability Question enclosed.

Answer 1

I think I understand the problem and would like to check my answer. A = {7}, B = {10,11,12}, C = empty set P(A U B U C) = 1/3

Answer 2

I'm afraid not. The main problem is that I don't think you know what the sample space is.

Answer 3

...what is your answer to part a?

Answer 4

The sample space S = {2,3,4,5,6,7,8,9,10,11,12}

Answer 5

@Bobo-i-bo

Answer 6

Sample space S should be all possible outcomes correct?

Answer 7

No, conisder the event of getting 2 on the first dice and then 2 on the second dice. This would be a different event to getting 1 on the first dice and 3 on the second dice. Agreed? But according to you, would they both correspond to the event of "4". Can you see why this is wrong?

Answer 8

Sample space only includes possible outcomes, not events to get there. I am not sure you understand the question.

Answer 9

And only possible outcomes is the set of numbers from 2 to 12....

Answer 10

The sample space is: {(1,1),(1,2),(1,3)...,(2,1),(2,2),(2,3)....(6,6)}. For example (3,4) corresponds to getting a 3 on the first dice and 4 on the second dice

Answer 11

An event is a subset of the sample space. To give you the right idea, let event Z be the event of the sum of dots getting 4. Then Z={(1,3),(2,2),(3,1)}.

Answer 12

Looking at my lecture notes my Professor is calling those events, which are a sub set of the outcome space S. Thanks, Ill keep working on it. My professor is only including possible outcomes in sample space S.

Answer 13

Everything @Bobo-i-bo said is correct. I just want to add that this:
- there is one way to obtain (1,1) as a result, and the probability of this is (1/6)*(1/6).
- there are two ways to obtain (1,2) as result, and the probability of this is 2*(1/6)*(1/6).

Think about this when computing probabilities.

Answer 14

Thank you both!