m in trigonometry, can some explain how the Law of Cosine and Law of Sine works when applying to a triangle that has 1side measurement missing and 2 angles inside missing. I just need to see the scenario. Thanks in advance

This is the formula that my instructor gives for Law of cosine
c2=a2+b2−2(a)(b)Cos(C)
For Law of Sine
a/Sin(a)=b/Sin(b)=C/Sin(C)

Question

m in trigonometry, can some explain how the Law of Cosine and Law of Sine works when applying to a triangle that has 1side measurement missing and 2 angles inside missing. I just need to see the scenario. Thanks in advance 

This is the formula that my instructor gives for Law of cosine
c2=a2+b2−2(a)(b)Cos(C)
For Law of Sine
a/Sin(a)=b/Sin(b)=C/Sin(C)

mathmale · Answer

Would you mind posting a spectific triangle, so that we could go about deciding which Law to use, the Law of Sines or the Law of Cosines?

anonymous · Answer

|dw:1459892268689:dw|