Please help, will MEDAL and FOLLOW! :) Write a vector equation of the line that passes through p(3,3) and is parallel to vector a=<9,-6)
parallel vectors ( Direction vector of the equation = <9,-6> ) Equation = Coordinate + Direction vector = (3,3)+<9,-6>t
@faiqraees Hi, sorry my internet froze for a couple minutes
Sorry I don't know how it fits
@reemii please help me
@irishboy123
@FaiqRaees is right. <x,y>=(3,3)+<9,-6>t is the equation other form: <x,y>=<12,3-6t>
so get a start point for the vector, and you've been given that! then get a direction for the vector, and you've been given that too!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @reemii @FaiqRaees is right. <x,y>=(3,3)+<9,-6>t is the equation other form: <x,y>=<12,3-6t> \(\color{#0cbb34}{\text{End of Quote}}\) Shouldn't the other form be <x,y>=<3+9t,3-6t>
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Again, @FaiqRaees , you are right. I forgot that little `\(t\)´.
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