Question

Statistics problem! Can some please teach me how to solve this?

Victoria has a bag containing 64 jellybeans. The jellybeans are red, white, black, and yellow. The probability of pulling a white jellybean from the bag is 25%. The probability of pulling a red is 1 out of 16. There are the same numbers of yello jellybeans as black. If a black jellybean is pulled out and eaten, what is the probability that the next jellybean to be pulled out will be Black?

Answer 1

\[\large \color{black}{\begin{align}
\begin{array}{|c|c|c|} \hline
Bean & Red & Black & White & Yellow \ \\ \hline
Probability &1/16 & & 0.25 & \\ \hline

\end{array}
\end{align}}\]
Can you complete the table?

Answer 2

B = 22 Y= 22

Answer 3

@Happpily Well I was looking for PROBABILITY but that will aslo work

Answer 4

\[ \large \color{black}{\begin{align}
\begin{array}{|c|c|c|} \hline
Bean & Red & Black & White & Yellow \ \\ \hline
Probability &1/16 &22/64 & 0.25 & 22/64\\ \hline

\end{array}
\end{align}} \]

Answer 5

Do I have to divide that?

Answer 6

What will be the probability to pick a Black bean after one pick?

Answer 7

21/63

Answer 8

very good
P(Black and Black) = P(Black) x P(Black)
= 22/64 x 21/63

Answer 9

Do I cross multiply?

Answer 10

No this is just fraction multiplication
\[\large\rm \frac{22}{64}*\frac{21}{63} \]

Answer 11

462/4,032

Answer 12

Simplify

Answer 13

8.727

Answer 14

No

Answer 15

11/96

Answer 16

Correct

Answer 17

So thats the answer?

Answer 18

Yes

Answer 19

No I think it isn't that complicated they are just asking the probability of the second black jellybean which is 21/63 = 1/3 Which is the answer

Answer 20

Yeah that's all they're asking. But what does the 11/96 have to do with it?

Answer 21

I'm a bit confused now lol

Answer 22

leave that

Answer 23

Just forget about it? How did you get 1/3 from 21/63?

Answer 24

21÷7/63÷7 = 1/3
And can you rephrase your second question

Answer 25

Nevermind. Thank you so much for your help. If it's not too much to ask can you rerun the steps for me to find the probability of the black jellybean after it is eaten. I got kind of confused after 11/96