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Mathematics 10 Online
OpenStudy (tylermckinney16):

help

OpenStudy (tylermckinney16):

Questions here

jimthompson5910 (jim_thompson5910):

You have a right triangle with legs 8 & 15. The hypotenuse is unknown a = 8 b = 15 c = x pythagorean theorem a^2 + b^2 = c^2 8^2 + 15^2 = x^2 solve for x

OpenStudy (tylermckinney16):

289^2??

OpenStudy (tylermckinney16):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

sorry @TylerMckinney16 I just saw that you tagged me

jimthompson5910 (jim_thompson5910):

8^2 + 15^2 is equal to 64+225 which becomes 289

jimthompson5910 (jim_thompson5910):

so x^2 = 289 now take the square root of both sides to find x

OpenStudy (tylermckinney16):

X = {-17, 17} @jim_thompson5910

OpenStudy (anonymous):

it is a triangle , no side can be negative `

jimthompson5910 (jim_thompson5910):

keep in mind that x represents a length

jimthompson5910 (jim_thompson5910):

so as @satellite73 is saying, it's impossible to have a negative length or distance. The only possible answer is x = 17

jimthompson5910 (jim_thompson5910):

|dw:1459909075204:dw|

jimthompson5910 (jim_thompson5910):

|dw:1459909098250:dw|

OpenStudy (tylermckinney16):

Oh ok so the answer is x=17

jimthompson5910 (jim_thompson5910):

I'm not thinking if x is this shaded piece here |dw:1459909123989:dw|

jimthompson5910 (jim_thompson5910):

then x would be 9 since 9+8 = 17 |dw:1459909156957:dw|

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