please i need help i will give a medal who ever helps!!!
with?
please help @ganeshie8!
@ParthKohli please help i need help!
@mathmale
Which part?
all of it!
Even a?
no
So the table?
yes
\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X)^2 \ \\ \hline 22& & \\ \hline & & \\ \hline & & \\ \hline & & \\ \hline \end{array} \end{align}}\]
Start by filling out the X column.
with what?
The given weights
in order or just the way its given?
In any order
ok then
So what will be the new table look like?
Like this right?
\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& & \\ \hline 18 & & \\ \hline 14& & \\ \hline 30& & \\ \hline 26& & \\ \hline \end{array} \end{align}}\]
that's what i got
X -(X) means the value of X - mean So 22 will be 22- mean 22-22 0
ok but what about the other empty columns like the x-x and the (x-x)2
Yeah but first fill out the X- X
So tell me the X-X (X-mean) values for the other sets of data
so for the second column i right for x-x is 22- then for the (x-x)2 is 22-22
Can you rephrase what you just said?
for the second column next to the numbers for x-x is 22- and for the (x-x)2 is 22-22? and for the other data set is it like 18-18 or 14-14 or is it 18-22 or 14-22? please help im getting confused.
Lets just focus on X-X and NOTon (X-X)² X-X is just Value - Mean So if the X is 13 then it will be 13-22
oh i thought it would be that way and it was
\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 22-22=0 & 0^2 \\ \hline 18 & & \\ \hline 14& & \\ \hline 30& & \\ \hline 26& & \\ \hline \end{array} \end{align}}\]
Can you complete the table?
yes but what about part c and d i don't understand that?
After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& 160 \\ \hline \end{array} \end{align}}\] Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{Σ(X-(X)^2)}{Number~of~values}}\]
ok now what how do i do that?
What is the value of Σ(x-(x))² ? HInt: Look at the table
so you take the like -4 to the power of 2 which is 16 and ?
im confused can you just tell what the answer is for c and d? please?
No Σ(x-(x))² = Add all the values in (x-(x))² column
i did that its full? im getting confused because i don't understand the standard deviation part?
I am explaining but please don't rush to the answer. First tell me what's the value of Σ(x-(x))²
can you give me the answer at least for the first one like an example so i can se one?
After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& \text{Add all the values in this column} \\ \hline \end{array} \end{align}}\]
that's what my table was looking like before now i odnt understand what standard devation.
In part c They are asking standard deviation right? That's what I am explaining
ok so the (x-x)2 means that how far numbers are spread out
Yes
@FaiqRaees now what?
After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& \text{Add all the values in this column} \\ \hline \end{array} \end{align}}\]
i added the values and got 160 is that correct?
Correct
Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{Σ(X-(X)^2)}{Number~of~values}}\]
Σ(x-(x))² = 160
so 22(22-(22))2=160
No Σ means sum So Σ(x-(x))² means sum of (x-(x))²
Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{160}{5}}\]
oh so like 16(18-(22))2=160 like that?
@FaiqRaees
Σ(x-(x))² = 0+16+64+64+16 Σ(x-(x))² = 160
160(22-(22))2
@FaiqRaees
please can you just tell me the answer because its due soon! please and i have somewhere to go so please tell me whats the answer?
Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{160}{5}}\]
so 160/16
@FaiqRaees
no what's the value of 160/5
its 32
@FaiqRaees
And the square root of 32 is?
5.65
@FaiqRaees
yes this is the standard deviation
ok now what?
@FaiqRaees
That's the asnwer of C
ok what about d
@FaiqRaees
@FaiqRaees
@FaiqRaees whats the answer for d
@FaiqRaees
@FaiqRaees
Faiq would be more likely to respond to your posts if you'd show all the work you've done, instead of asking a wide-open question such as "What aboput D?" Same with me.
ok so can you help me?
@FaiqRaees i got the part c correct but im trying to understand and try to the answer for part d can you please help me?
Join our real-time social learning platform and learn together with your friends!