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Mathematics 18 Online
OpenStudy (anonymous):

please i need help i will give a medal who ever helps!!!

OpenStudy (anonymous):

with?

OpenStudy (anonymous):

please help @ganeshie8!

OpenStudy (anonymous):

@ParthKohli please help i need help!

OpenStudy (anonymous):

@mathmale

OpenStudy (faiqraees):

Which part?

OpenStudy (anonymous):

all of it!

OpenStudy (faiqraees):

Even a?

OpenStudy (anonymous):

no

OpenStudy (faiqraees):

So the table?

OpenStudy (anonymous):

yes

OpenStudy (faiqraees):

\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X)^2 \ \\ \hline 22& & \\ \hline & & \\ \hline & & \\ \hline & & \\ \hline \end{array} \end{align}}\]

OpenStudy (faiqraees):

Start by filling out the X column.

OpenStudy (anonymous):

with what?

OpenStudy (faiqraees):

The given weights

OpenStudy (anonymous):

in order or just the way its given?

OpenStudy (faiqraees):

In any order

OpenStudy (anonymous):

ok then

OpenStudy (faiqraees):

So what will be the new table look like?

OpenStudy (faiqraees):

Like this right?

OpenStudy (faiqraees):

\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& & \\ \hline 18 & & \\ \hline 14& & \\ \hline 30& & \\ \hline 26& & \\ \hline \end{array} \end{align}}\]

OpenStudy (anonymous):

that's what i got

OpenStudy (faiqraees):

X -(X) means the value of X - mean So 22 will be 22- mean 22-22 0

OpenStudy (anonymous):

ok but what about the other empty columns like the x-x and the (x-x)2

OpenStudy (faiqraees):

Yeah but first fill out the X- X

OpenStudy (faiqraees):

So tell me the X-X (X-mean) values for the other sets of data

OpenStudy (anonymous):

so for the second column i right for x-x is 22- then for the (x-x)2 is 22-22

OpenStudy (faiqraees):

Can you rephrase what you just said?

OpenStudy (anonymous):

for the second column next to the numbers for x-x is 22- and for the (x-x)2 is 22-22? and for the other data set is it like 18-18 or 14-14 or is it 18-22 or 14-22? please help im getting confused.

OpenStudy (faiqraees):

Lets just focus on X-X and NOTon (X-X)² X-X is just Value - Mean So if the X is 13 then it will be 13-22

OpenStudy (anonymous):

oh i thought it would be that way and it was

OpenStudy (faiqraees):

\[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 22-22=0 & 0^2 \\ \hline 18 & & \\ \hline 14& & \\ \hline 30& & \\ \hline 26& & \\ \hline \end{array} \end{align}}\]

OpenStudy (faiqraees):

Can you complete the table?

OpenStudy (anonymous):

yes but what about part c and d i don't understand that?

OpenStudy (faiqraees):

After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& 160 \\ \hline \end{array} \end{align}}\] Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{Σ(X-(X)^2)}{Number~of~values}}\]

OpenStudy (anonymous):

ok now what how do i do that?

OpenStudy (faiqraees):

What is the value of Σ(x-(x))² ? HInt: Look at the table

OpenStudy (anonymous):

so you take the like -4 to the power of 2 which is 16 and ?

OpenStudy (anonymous):

im confused can you just tell what the answer is for c and d? please?

OpenStudy (faiqraees):

No Σ(x-(x))² = Add all the values in (x-(x))² column

OpenStudy (anonymous):

i did that its full? im getting confused because i don't understand the standard deviation part?

OpenStudy (faiqraees):

I am explaining but please don't rush to the answer. First tell me what's the value of Σ(x-(x))²

OpenStudy (anonymous):

can you give me the answer at least for the first one like an example so i can se one?

OpenStudy (faiqraees):

After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& \text{Add all the values in this column} \\ \hline \end{array} \end{align}}\]

OpenStudy (anonymous):

that's what my table was looking like before now i odnt understand what standard devation.

OpenStudy (faiqraees):

In part c They are asking standard deviation right? That's what I am explaining

OpenStudy (anonymous):

ok so the (x-x)2 means that how far numbers are spread out

OpenStudy (faiqraees):

Yes

OpenStudy (anonymous):

@FaiqRaees now what?

OpenStudy (faiqraees):

After completing your table will look like this \[\large \color{black}{\begin{align} \begin{array}{|c|c|c|} \hline X & X-(X) & (X-(X))^2 \ \\ \hline 22& 0 & 0 \\ \hline 18 & -4 & 16 \\ \hline 14& -8&64 \\ \hline 30& 8&64 \\ \hline 26&4 &16 \\ \hline Σ& 0& \text{Add all the values in this column} \\ \hline \end{array} \end{align}}\]

OpenStudy (anonymous):

i added the values and got 160 is that correct?

OpenStudy (faiqraees):

Correct

OpenStudy (faiqraees):

Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{Σ(X-(X)^2)}{Number~of~values}}\]

OpenStudy (faiqraees):

Σ(x-(x))² = 160

OpenStudy (anonymous):

so 22(22-(22))2=160

OpenStudy (faiqraees):

No Σ means sum So Σ(x-(x))² means sum of (x-(x))²

OpenStudy (faiqraees):

Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{160}{5}}\]

OpenStudy (anonymous):

oh so like 16(18-(22))2=160 like that?

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

Σ(x-(x))² = 0+16+64+64+16 Σ(x-(x))² = 160

OpenStudy (anonymous):

160(22-(22))2

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (anonymous):

please can you just tell me the answer because its due soon! please and i have somewhere to go so please tell me whats the answer?

OpenStudy (faiqraees):

Now to find out standard deviation, apply the formula \[std = \sqrt{\frac{160}{5}}\]

OpenStudy (anonymous):

so 160/16

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

no what's the value of 160/5

OpenStudy (anonymous):

its 32

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

And the square root of 32 is?

OpenStudy (anonymous):

5.65

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

yes this is the standard deviation

OpenStudy (anonymous):

ok now what?

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

That's the asnwer of C

OpenStudy (anonymous):

ok what about d

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (anonymous):

@FaiqRaees whats the answer for d

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (mathmale):

Faiq would be more likely to respond to your posts if you'd show all the work you've done, instead of asking a wide-open question such as "What aboput D?" Same with me.

OpenStudy (anonymous):

ok so can you help me?

OpenStudy (anonymous):

@FaiqRaees i got the part c correct but im trying to understand and try to the answer for part d can you please help me?

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