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OpenStudy (ittybitty14):
what is 3 square root of 135?
A.
5 3 root of 2
B.
2 3 root of 5
C.
5 3 root of 3
D.
3 3 root of 5
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OpenStudy (ittybitty14):
MEDAL AND FAN!!!!!!!!!!!
OpenStudy (welshfella):
first find the prime factors of 135
OpenStudy (ittybitty14):
I think it's 3^3 x 5
OpenStudy (welshfella):
its 3*3*3*5
can we get a perfect square from these numbers?
OpenStudy (ittybitty14):
Yes?
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OpenStudy (welshfella):
oh i misread the question!
you want the cube root of 135
(\[\sqrt[3]{135}\]
OpenStudy (mathmale):
If the index of your root is 2, you have a square root.
If the index is 3, you have a cube root (not a 3 square root).
OpenStudy (welshfella):
= \[\sqrt[3]{27} * \sqrt[3]{5}\]
OpenStudy (mathmale):
I agree with welshfella: you want the third root of 135.
Look at the way he has factored 135. What do you think was his purpose in doing that?
OpenStudy (welshfella):
yes the '3 square root' confused me.
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OpenStudy (mathmale):
What is the "nice" third root of 27? Does 5 have a "nice" third root (i. e., with NO decimal fraction)?
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