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if tan(alpha+beta)=a+b and tan(alpha-beta)=a-b prove that atan(alpha)-btan(beta)=a^2-b^2
what math is that?
if \[\tan(\alpha+\beta)=a+b\] and \[\tan(\alpha-\beta)=a-b\] prove that \[atan \alpha-btan \beta=a^2-b^2\]
@ganeshie8
i guess you can use the following tan identities tan (A + B) = tanA tan B ----------- 1 - tan A tan B and tan( A - B) = tan A tan B ---------- 1 + tan A tan B
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after that?
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