Mathematics
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OpenStudy (sagewilson):
Find the total area for the regular pyramid.
Image below
(144 + _ _ √_ )
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OpenStudy (sagewilson):
OpenStudy (sagewilson):
I need to find the base area, I do not know how I would do that for this figure.
OpenStudy (juliannegirltomboy):
12x10
OpenStudy (juliannegirltomboy):
divided by 2
OpenStudy (sagewilson):
Okay, that would give me 60, I'm assuming the √ would be 2. But I am not sure.
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OpenStudy (juliannegirltomboy):
then is has 144+so ad that to 60
OpenStudy (sagewilson):
I don't really need to add it, my answer has to be 144 + ?? √? I do not know how I would get the measurement of √ would be.
OpenStudy (juliannegirltomboy):
the answer is 144+60/_
OpenStudy (juliannegirltomboy):
so after that plus put 60
OpenStudy (sagewilson):
That's not the full answer though, also I would like to know how you got that so I can use it as a reference in my other questions.
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OpenStudy (juliannegirltomboy):
i got 60 by 12x10 divided by 2
OpenStudy (sagewilson):
Okay. But the measurements of the base are 12 and 12. Wait. I think I figured out how to do it.
OpenStudy (juliannegirltomboy):
you see
OpenStudy (juliannegirltomboy):
just tag me if you need more help
OpenStudy (sagewilson):
okay.
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OpenStudy (anonymous):
92.79 sq units. (3 times 1/2 base times ht)
OpenStudy (anonymous):
my bad...add the area of the base...which is 62.34...so total surface area =155.13
OpenStudy (juliannegirltomboy):
good job