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Mathematics 6 Online
OpenStudy (sagewilson):

Find the total area for the regular pyramid. Image below (144 + _ _ √_ )

OpenStudy (sagewilson):

OpenStudy (sagewilson):

I need to find the base area, I do not know how I would do that for this figure.

OpenStudy (juliannegirltomboy):

12x10

OpenStudy (juliannegirltomboy):

divided by 2

OpenStudy (sagewilson):

Okay, that would give me 60, I'm assuming the √ would be 2. But I am not sure.

OpenStudy (juliannegirltomboy):

then is has 144+so ad that to 60

OpenStudy (sagewilson):

I don't really need to add it, my answer has to be 144 + ?? √? I do not know how I would get the measurement of √ would be.

OpenStudy (juliannegirltomboy):

the answer is 144+60/_

OpenStudy (juliannegirltomboy):

so after that plus put 60

OpenStudy (sagewilson):

That's not the full answer though, also I would like to know how you got that so I can use it as a reference in my other questions.

OpenStudy (juliannegirltomboy):

i got 60 by 12x10 divided by 2

OpenStudy (sagewilson):

Okay. But the measurements of the base are 12 and 12. Wait. I think I figured out how to do it.

OpenStudy (juliannegirltomboy):

you see

OpenStudy (juliannegirltomboy):

just tag me if you need more help

OpenStudy (sagewilson):

okay.

OpenStudy (anonymous):

92.79 sq units. (3 times 1/2 base times ht)

OpenStudy (anonymous):

my bad...add the area of the base...which is 62.34...so total surface area =155.13

OpenStudy (juliannegirltomboy):

good job

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