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Mathematics 6 Online
OpenStudy (littlet):

what is the area of the sector in circle B below (Give me a Minute i will need to draw Picture) Show your calculations

OpenStudy (littlet):

|dw:1460064913383:dw| this is the picture

OpenStudy (littlet):

I am not really understanding how those tie into my problem.

OpenStudy (jdoe0001):

\(\textit{area of a circle's sector}=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=\textit{angle in degrees}\\ r=radius \end{cases}\)

OpenStudy (jdoe0001):

so, you're given both, angle and radius, plug and chug

OpenStudy (littlet):

yes sorry had something weird happen hold on going to plug it in

OpenStudy (littlet):

27TT15 2^/360 is this right?

OpenStudy (littlet):

TT stands for Pie

OpenStudy (littlet):

@phi @jdoe0001 is this right?

OpenStudy (jdoe0001):

yes

OpenStudy (littlet):

The 15x15 = 225. is the next step right?

OpenStudy (jdoe0001):

225 y es

OpenStudy (jdoe0001):

\(\bf \cfrac{27\cdot \pi \cdot 15^2}{360}\) so... .get a decimal value there, and that's the circle's sector :)

OpenStudy (anonymous):

\[\frac{27 \pi 15^2}{360}=\frac{135 \pi }{8}=53.0144 \]

OpenStudy (littlet):

27 x 3.14 = 84.78 x 225= 19075.5/360= 52.9875?

OpenStudy (jdoe0001):

well, using 3.14 for \(\pi\), I'd think so, yes

OpenStudy (littlet):

alright. Thank you.

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

well, using 3.14 for π, I'd think so, yes The above is correct.

OpenStudy (littlet):

ok thank you as well! have a good night

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