Quadrilateral ABCD is inscribed in circle N, as shown below. What is the measure of
http://www.mathopenref.com/quadrilateralinscribedangles.html <--- what do you think it may be?
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@jdoe0001 please help i have 10 mins
i have ten mins to explain and figure out the answer
well, did you see the "inscribed quadrilateral conjecture"? the opposite angles are 180, or "supplementary angles"
@jdoe0001 im lost
so... I assume you haven't seen the link above? http://www.mathopenref.com/quadrilateralinscribedangles.html
i did
i just don't understand it
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@jhonyy9
solve for "x" then to find angle ABC, just use the found "x" in 4x+1 :)
how would i solve for x?
@jdoe0001
im so lost
hmm well (4x+1) + (2x-7) = 180 remove the parentheses simplify, solve for "x", or "isolate" x
4+1 2-7?
5-5?
4+1? seems to assume x =1 but we dunno what "x" is so... solve for "x"
6x-6=180
yeap 6x - 6 = 180 then 6x = 180 +6 \(x=\cfrac{180+6}{6}\)
the answer is 125 right?
how you have got for x 125 ?
yes right bc x=31 so 4x+1=125 right sure
nah k you :)
i can't give u both a medal though
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