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Mathematics 8 Online
OpenStudy (anonymous):

fan and medal! please help, how do i do this question? https://i.gyazo.com/82745e3c4f75db58ac943428a7b4c534.png

OpenStudy (anonymous):

like how do I find the answer

OpenStudy (anonymous):

what's the equation for an ellipse?

OpenStudy (anonymous):

There is 2, one for each of the two ellipse types right?

OpenStudy (anonymous):

yep, what are they?

OpenStudy (anonymous):

horizontal is (x-h)^2 / a^2 + (y-k)^2 / b^2 =1 and vertical is (x-2)^2/b^2 + (y-k)^2 / a^2 = 1

OpenStudy (anonymous):

and how do you differentiate between the two?

OpenStudy (anonymous):

the bottom part of the equation is reversed in the vertical equation

OpenStudy (anonymous):

no, I'm saying when do you use horiz and when do you use vert?

OpenStudy (anonymous):

I'm not sure on that part, our teacher didn't really give us much to work with

OpenStudy (anonymous):

all good. that's what I'm here for! you use the horizontal equation when the foci are on the left and right. (y=0, x=something) you use the vertical equation when the foci are above and below (y=something, x=0) so you know now that you have to use which equation?

OpenStudy (anonymous):

I believe vertical?

OpenStudy (anonymous):

cool! now here's what you do with the directrix. \[y=a^2/c\] is the directrix equation

OpenStudy (anonymous):

c is the foci distance from 0.

OpenStudy (anonymous):

Not to rush you but I have to pack up and shut down my computer pretty soon and so I did something really quickly and I think I have the answers, I believe it is C?

OpenStudy (anonymous):

I'll be another minute, you're close to the answer! and with knowledge of a^2, you plug in 3 for c. a^2=25, a=5. then to find b, it's b^2 = a^2 – c^2 b^2=25-9=16 b=4 plug in and you're done

OpenStudy (anonymous):

b=4 a=5 so it's A yay!

OpenStudy (anonymous):

Thank you !! I understand now

OpenStudy (anonymous):

cool! just memorize the equations, it'd tedious but easier understanding-wise than you'd think!

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