fan and medal! please help, how do i do this question? https://i.gyazo.com/82745e3c4f75db58ac943428a7b4c534.png
like how do I find the answer
what's the equation for an ellipse?
There is 2, one for each of the two ellipse types right?
yep, what are they?
horizontal is (x-h)^2 / a^2 + (y-k)^2 / b^2 =1 and vertical is (x-2)^2/b^2 + (y-k)^2 / a^2 = 1
and how do you differentiate between the two?
the bottom part of the equation is reversed in the vertical equation
no, I'm saying when do you use horiz and when do you use vert?
I'm not sure on that part, our teacher didn't really give us much to work with
all good. that's what I'm here for! you use the horizontal equation when the foci are on the left and right. (y=0, x=something) you use the vertical equation when the foci are above and below (y=something, x=0) so you know now that you have to use which equation?
I believe vertical?
cool! now here's what you do with the directrix. \[y=a^2/c\] is the directrix equation
c is the foci distance from 0.
Not to rush you but I have to pack up and shut down my computer pretty soon and so I did something really quickly and I think I have the answers, I believe it is C?
I'll be another minute, you're close to the answer! and with knowledge of a^2, you plug in 3 for c. a^2=25, a=5. then to find b, it's b^2 = a^2 – c^2 b^2=25-9=16 b=4 plug in and you're done
b=4 a=5 so it's A yay!
Thank you !! I understand now
cool! just memorize the equations, it'd tedious but easier understanding-wise than you'd think!
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