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OpenStudy (bigpapa1):
Simplify
RhondaSommer (rhondasommer):
okay so what you do is subtract the exponents. 3-3 = 0 so you wont have r any where in the equation
RhondaSommer (rhondasommer):
you go bottom - minus top so now you have 2-4 is what?
OpenStudy (bigpapa1):
2 minus 4 is 2
RhondaSommer (rhondasommer):
close. negative two.
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RhondaSommer (rhondasommer):
so now you have 4-(1) there is no exponent written but it is (1)
RhondaSommer (rhondasommer):
(we are doing (t) now
RhondaSommer (rhondasommer):
still there?
OpenStudy (bigpapa1):
Uh yeah
RhondaSommer (rhondasommer):
you are cunfused arent you?
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OpenStudy (bigpapa1):
Oh yeah lol
RhondaSommer (rhondasommer):
okay. If i have \[t ^{3}a^{-3}\] I would switch the \[a^{-3}\] to the top and make it a positive.
so:
\[t^3a^{-3}\]is the same as \[\frac{ a^{3} }{ t^3 }\]
RhondaSommer (rhondasommer):
so what we are doing is pulling them back down.
your equation is \[\frac{ r^3s^4t }{ r^3s^2t^4 }\]
that is the same thing as
\[r^3r^{-3}s^2s^{-4}t^4t^{-1}\]
RhondaSommer (rhondasommer):
so \[r^3~and~r^{-3}\]cancel each other out
OpenStudy (bigpapa1):
Ohh okay
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RhondaSommer (rhondasommer):
so now, you have \[s^2~and~s^{-4}\] 2-4 is negative 2 so you are going to put it as \[s^{-2}\] and we will deal with that later
RhondaSommer (rhondasommer):
you do the (t's) \[t^4~and~t^{-1}\]equals what
OpenStudy (bigpapa1):
5
RhondaSommer (rhondasommer):
take the exponents and make them thier own equation. 4+(-1) is what?
OpenStudy (bigpapa1):
3
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RhondaSommer (rhondasommer):
yep. so now you have \[s^{-2}~and~t^3\] remember the example i gave you earlier? how a was a negative so we made it a fraction and put it on the top to make it a positive?
OpenStudy (bigpapa1):
Yeah..... I think I got it now thanks
RhondaSommer (rhondasommer):
your welcome :)
RhondaSommer (rhondasommer):
im just trying to help :/
OpenStudy (bigpapa1):
No its okay :)
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RhondaSommer (rhondasommer):
oh okay. i was just trying to help you through the entire problem. Im sorry if i offended you somehow?