Solve the quadratic equation 5x^2-8x=8-5x
How do we start?
We start by adding 5x to both sides
Right. We want one side to be equal to zero. So after we add 5x to both sides, we subtract 8 from both sides\[5x ^{2}-3x-8=0\]
What do we do next?
Factor?
Right
why not just plug numbers into the solution equation, factoring seems to be kind of difficulty
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@mathmale We need a moderator
so does this d-i-c-k
@caozeyuan Plugging numbers in may get you the right answer, but it would take forever. Not to mention that you might not even find all the possible answers.
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and if you are studying quadratic equations you have to learn how to factor them.
but the solution equation ganratees all solutions will be found, and factoring is hard espeicially if you have complex conjugate roots
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@HannahC234 So sorry about this. Do you need help factoring?
Yes please
Ok, 5x^2-3x-8=0 For factoring a quadratic, we need to find what will add up to -3x and what will multiply to be negative 8: (5x-?)(x+?)
Okay. I'm still kinda lost
(5x-8)(x+1) is the next step. Do you know how to FOIL?
Yes
So if we FOIL, (5x-8)(x+1) equals: 5x^2+5x-8x-8 or 5x^2-3x-8 We know that (5x-8)(x+1) is equal to zero. So: 5x-8=0 AND x+1=0 Can you simplify these equations to find the values of x?
-1 and 8/5 would be the answer correct?
Hannah: Substitute (-1) for x in the original equation. is the equation then true or false? That will tell you whether or not -1 is a solution.
So it would be -1?
"-1 and 8/5 would be the answer correct? " Both of those would are the right answers. If you plug them into the original equation, you'll see that they work.
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