Question

need some help with a question, it is sigma, from 1 to infinity, 3n/(3^sqrt n^4)

Answer 1

Is this the question:
\[\sum_{n=1}^{\infty}\frac{3n}{\sqrt{3}n^4}\]
?

Answer 2

the bottom is the 3 sqrt of n^4

Answer 3

was not thinking

Answer 4

So this:
\[\sum_{n=1}^{\infty}\frac{ 3n }{ 3\sqrt{n^4} }\]
?

Answer 5

oooh

Answer 6

i get it now :P

Answer 7

\[\sum_{n=1}^{\infty}\frac{ 3n }{ \sqrt[3]{n^4} }\]

Answer 8

Okay, so do you know how to manipulate indices?

Answer 9

yeah lol, i just need somw help in seeing which method for a infinite series, like alternating series, ratio method, etc.

Answer 10

Haha, sorry, kk :P

Answer 11

Let me think ^_^

Answer 12

thank you

Answer 13

Comparison test

Answer 14

awesome thanks