Question

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
a. ±i√3
b. ±i
c. ±2
d. ±1
e. ±1, ±i√3

Answer 1

help

Answer 2

have you tried it ?

Answer 3

i get c

Answer 4

can you show your work ?

Answer 5

ill try

Answer 6

hI!!

Answer 7

ok that was totally wrong
you have to find \[K(H(x))\]first

Answer 8

h(x)=X^2+1; k(x)=-x^2=4
k(h)=k(x^2+1)=-(x^2+1)^2+4=0
(x^2+1)^2 x^2 +1= pm 2
x^2+1=-2 or x^2+1=2
\[x=\pm i \sqrt{3}\]

Answer 9

that????