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are you asking is it correct?
@ibrafacts
I don't think it is :(
@elitedamosh
let g(x)=y y=-(x-4(x+2)\[y=-(x^2+2x-4x-8)=-(x^2-2x-8)=-(x^2-2x+1-9)=-(x^2-2x+1)+9\] \[or~y=-(x-1)^2+9\] vertex of g(x) is (1,9) maximum value of g(x)=9 maximum value of f(x)=9+3=12
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correction last line maximum of f(x)=4 so maximum value of g(x) is 9-4=5 more than maximum of f(x)
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