Question

An amateur rocketry club is holding a competition. There is a cloud cover at 1000 ft. If a rocket is launched with a velocity of 315ft/s, use the function h(t) = -16t^2+ vt + h_0 to determine how long the rocket is out of sight.

Answer 1

@phi @jim_thompson5910

Answer 2

-16t^2 + 315t + 1000 = 0

Answer 3

imagine the rocket taking off and following this path

Answer 4

the height of the rocket at time t is


h(t) = -16t^2+ vt + h_0
h(t) = -16t^2+ 315t + 0
h(t) = -16t^2+ 315t

set this height equal to 1000

h(t) = -16t^2+ 315t
1000 = -16t^2+ 315t

now solve for t