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I'm a little confused with finding the standard form. Would someone please help me? Write the following equation in standard form. Then solve
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Yes?
\[5q ^{2}-4q=4q^2-8q+45\]
you want to put everything on one side of the equal sign
The standard form of a quadratic equation is \[ax^2+bx+c=0\]
easiest would be to subtract \(4q^2\) add \(8q\) and subtract \(45\) from both sides
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\[5q^2-q^2-8q+45\] Where would we add 8q?
it is not \[5q^2-q^2\] it is \[5q^2-4q^2\]
So it would stay the same even after we cross it out?
i am not sure what you mean what is 5 apples minus 4 apples?
1
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1 what?
|dw:1460593719533:dw| Isn't that what you meant?
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