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The work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below: Step 1: 3(3y − 8) = 10 + 3y Step 2: 6y − 5 = 10 + 3y Step 3: 3y − 5 = 10 Step 4: 3y = 15 Step 5: y = 5 In which step did the student first make an error and what is the correct step?
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http://lv.k12.com/mediaFiles/Ninth_Grade/Math/Unit17525/Lesson68693/VHS_PA_S2_03_L210_L310_LQ_Q2.gif
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@Ashleyisakitty
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What does the picture have to do with the problem: http://lv.k12.com/mediaFiles/Ninth_Grade/Math/Unit17525/Lesson68693/VHS_PA_S2_03_L210_L310_LQ_Q2.gif
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