Question

Hi, I need help on this math question that's going to be on my exam... in about an hour. I need help! I give medals! **
This is the question: Admission to a basketball game was $1 for students and $2 for adults. The number of tickets sold for students was 80 more than the number of adult tickets sold. If the total amount of money came out to $980, how many of each ticket was sold?

It's very hard for me as I don't know how to set this up and actually do it, I'm not the best in algebra, I tried but got weird answers. Thank you !

Answer 1

let the no. of students =x

no.of adults = y

admission fee for 1 student =1$
admission fee for 1 adult =2$

total amt = 980

x + 2y =980 ------(1)

students = adults +80 [students are 80 more than adults]

x= y+80 ------(2)

substitute (2) in (1)

y+80 +2y = 980

3y +80 =980

3y = 980-80

3y = 900

y= 900/3

y = 300

there for no of adults are y = 300

plug y= 300 in (2) you can get x

Answer 2

Thank you so much!! <3