Question

Jermiah is factoring 0.64t^24-9 by using a^2-b^2=(a+b)(a-b). Which expression will he use for the value of a?

Answer 1

@Bobo-i-bo

Answer 2

i think 0.64

Answer 3

Why?

Answer 4

yahoo lol

Answer 5

Well yahoo is very wrong :P

Answer 6

thought so lol

Answer 7

So \(0.64t^{24}-9\) is in the form of the difference of two squares, i.e. it is the square of one number... let's say \(a\), minus the square of another number which we'll call \(b\). In other words it is in the form \(a^2-b^2\). So you have to find what \(a\) is. Following me? Do you understand better/see what you have to do?

Answer 8

0.64t^24-x^2

Answer 9

?

Answer 10

idk lol

Answer 11

i was trying to find a

Answer 12

If I tell you that 0.64t^2-9 is in the form of a^2-b^2, then a^2=0.64t^24 and b^2=9

Answer 13

Basically the square of a is equal to 0.64t^24 and the square of b is equal to 9, so what is b and what is a?

Answer 14

a=0.64t^24 and b=9

Answer 15

nono, the SQUARE of a is equal to 0.64t^24 and the SQUARE of b is equal to 9. a is not equal to 0.64t^24 and b is not equal to 9

Answer 16

So basically
\(a^2=0.64t^{24}\) and \(b^2=9\)

Answer 17

ohh ok

Answer 18

i just forgot to square a and b

Answer 19

so what's a and what is b?

Answer 20

am i supposed to put 0.64t^24 in my calculator?