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In the quadratic equation ax2 + bx + c = 0, if b2 - 4ac > 0, which of the following is true of the equation? A. It has two real solutions. B. It has one real solution. C. It has two complex solutions.
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@rebeccaxhawaii @robtobey @surjithayer
The quadratic formula solves the above equation. \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
i dont understand that
when discriminant>0 it has real roots.
only 1 real root?
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\(b^2 - 4ac \) This part of the quadratic equation is called the discriminant. If the discriminant is positive, there are two real solutions. If the discriminant is zero, there is one real solution. If the discriminant is negative, there are two complex solutions.
thank you (:
You're welcome.
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