Question

If the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expression in the parabola's equation?

A. 8
B.4
C.2
D.6

Answer 1

looks like \[y=a(x-h)^2+k\] where the vertex is \((h,k)\) which in your case is \((-4,6)\) so you start with \[y=a(x+4)^2+6\]now you only have to find \(a\)

Answer 2

the only other thing you know is that \((-3,14)\) is on the graph
put \(x=-3\) and \(y=14\) and solve \[14=a(-3+4)^2+6\]for \(a\)

Answer 3

To solve for, " a " would you have to distribute it ?

Answer 4

oh no

Answer 5

do the arthmetic first
what is \((-3+4)^2\)?

Answer 6

ok ok i seem to be understanding it a lot better now

Answer 7

what did you get?

Answer 8

A. 8?

Answer 9

yeah looks good to me

Answer 10

thank you

Answer 11

yw