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@Aveline
@FaiqRaees
Sorry, I'm not any good at proofs.
@FaiqRaees
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@Directrix
AC= AB = radius = R AE is shared by triangles: ACE and ABE, Angle AEC = Angle AEB = 90 degrees Therefore, ACE and ABE are congruent via SAS rule. (Side, Angle, Side) Therefore CE and EB ; Sides of triangles ACE and ABE respectively, are the same -- Angles CAE and BAE are the same as triangles ACE and ABE are congruent. Assume angles CAE/BAE = x The arc length of a fraction of a circle = radius * x, where x is the angle in radians CD = x*radius BD = x*radius Therefore CD and BD are equal.
Is that the answer?
@Directrix
@SageWilson
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@563blackghost
@Mythorius
I'm not good with this stuff
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