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Hi guys, I have this problem: A square has its length increased by 4 feet and its width decreased by 3 feet; the resulting area is 144 feet. What was the original area of the square? I don't even know how to start this problem to solve...
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|dw:1460729083391:dw|
length was 8 feet and width was 15
Since it was originally a square, the length and width are equal. Ok so far?
@ssddss02 How can a square have different length and width?
Yeah I get that mathstudent.
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Now we modify it according to the problem.
My bad sorry
I tried a part and \i got (l+4)(w-3)=144 otherwise idk what to do..
|dw:1460729202070:dw|
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