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Mathematics 14 Online
OpenStudy (littlet):

Could someone help me out? A hot air balloon holds 3,249 cubic meters of helium. The density of helium is 0.1785 kilograms per cubic meter. How many kilograms of helium does the balloon contain, rounded to the nearest tenth of a kilogram? 1,873.4 kg 2,194.6 kg 2,721.2 kg 579.9 kg

OpenStudy (qwertty123):

Use the formula of density here : \[p=\frac{ mass }{ volume}\] where ρ ( pronounced as rho) is the density of the substance (here substance is Helium) Given to you that density of helium in the balloon: \[PHe=0.1785kgm^-3\] And given that volume of Helium gas in the balloon = 4,328 m^3

OpenStudy (qwertty123):

So, it is actually volume of helium gas and the density Since, density = mass/ volume So, mass = density * volume...

OpenStudy (littlet):

So 0.1785x3249?

OpenStudy (qwertty123):

Mass = Volume * Density = 4328 * 0.1785

OpenStudy (littlet):

oh ok

OpenStudy (littlet):

77.25

OpenStudy (littlet):

772.5 sorry @Qwertty123 put the decimal point to early lol

OpenStudy (qwertty123):

lol Nice job! Yes that is right.

OpenStudy (littlet):

wait that is none of my options @Qwertty123

OpenStudy (littlet):

not one of*

OpenStudy (qwertty123):

Oh my.. I put the wrong numbers in.. :/

OpenStudy (qwertty123):

You where right about the numbers my bad...So do your numbers to get the right answer..

OpenStudy (littlet):

Alright thank you

OpenStudy (littlet):

Yep it is D. 579.9 Thank you so much!

OpenStudy (qwertty123):

You welcome :)

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