Question

http://prntscr.com/at86fb

Answer 1

@RhondaSommer

Answer 2

i accidentally closed it what the heck :(

Answer 3

he didnt factor it correctly

Answer 4

Bo is dumb then xD

Answer 5

\[x^2-8xy\]shouldbe\[x(x-8y)\]then you have the second half which was right and it is \[-2y(x-8y)\]and you can combine the \[(x-8y)\] parts of both the sides and make it \[(x-2y)(x-8y)\]

Answer 6

and idk how to answer b

Answer 7

ok no worries! thank you for ur help

Answer 8

@hartnn do u know how to do this ;~;

Answer 9

here i got it.
When a and c are positive, two factors of ac must add to equal |b|. In this case ac = 1(16) = 16. Two factors of 16, 2 and 8 add up to the absolute value of b. |-10| = 10.
If ac is negative, two factors of ac must have a difference of |b

Answer 10

thank you thank you! @RhondaSommer

Answer 11

no prob