Malcolm paid an average of $31 per tie for a recent purchase of three ties. The price of one tie was twice as much as another, and the remaining tie cost $24, what were the prices of the other two ties?

Question

dayakar · Answer

let cost of first tie = x
 cost of second tie = 2x
cost of third tie = 24

average cost = $31

$$\frac{ \sum of the costs of three ties }{ no. of ties } = average$$

dayakar · Answer

$$\frac{ x+2x+ 24 }{ 3 } = 31$$

find x

mathstudent55 · Answer

Another approach:
The average price of the three ties was $31.
That means all three ties cost 3 * $31 = $93.
The first tie cost $24.
Subtract the known cost: $93 - $24 = $69

Now you need to find the prices of two ties, knowing that one cost twice the other, and together they cost $69.

x + 2x = $69

Solve for x to find the price of the second tie.
Then multiply x by 2 to find the price of the third tie.

pphalke · Answer

@mathstudent55 its 23 
because you get 3x=69 then u divide by 3 and get 23
what do I do next

faiqraees · Answer

24+x+2x = 3 * 31

pphalke · Answer

what was the price of the less expensive of the two remaining ties? its asking that

faiqraees · Answer

the value of x is the answer to your current question

pphalke · Answer

faiqraees I did all that it came out as a decimal that doesn't sound right

mathstudent55 · Answer

Correct.
x = 23 is the price of one tie.
Now the other tie was 2x, so multiply 23 by 2.

mathstudent55 · Answer

First tie we were told was $24.
Second tie, you calculated $23. This was x.
Third tie is 2x, so it is simply 2 times $23.

mathstudent55 · Answer

BTW, I did write above what you need to do to find the prices of the other two ties:

"x + 2x = $69 
Solve for x to find the price of the second tie. 
Then multiply x by 2 to find the price of the third tie."

pphalke · Answer

23*2 is 46 @mathstudent55