Question

Write two sets of parametric equations for .....y=x^4-1 @jim_thompson5910

Answer 1

I used 20t

Answer 2

One set I can think of off the top of my head is this

x = t
y = t^4-1

notice how because x = t, we can effectively replace every copy of 't' with x in the second equation

Answer 3

i did 20t=x^4-1

Answer 4

I'm not sure how you got 20t=x^4-1

Answer 5

instead of using t...im using 20t

Answer 6

i replaced y with 20t

Answer 7

this isnt the answer, its the first thing i set up

Answer 8

do you see how I got

x = t
y = t^4-1

Answer 9

yes

Answer 10

that's one set. I'm trying to think of the other

Answer 11

let's solve y = t^4-1 for t

y = t^4-1
y+1 = t^4
t^4 = y+1
t = (y+1)^(1/4)

if y = t, then x = (y+1)^(1/4) = (t+1)^(1/4)

to ensure that x is both positive and negative, we use plus/minus, so the other set would be

\[\Large \begin{cases}x = \pm(t+1)^{1/4} \\ {} \\ y = t\end{cases}\]

Answer 12

ty

Answer 13

no problem