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Mathematics 7 Online
OpenStudy (faiqraees):

suggest why a thin rod can bend more than thick rod WITHOUT BREAKING? (It has to be assumed that both rods are of same material)

OpenStudy (faiqraees):

?

OpenStudy (carolina4567):

The thicker a rod is, the more stress there will be between one side and another when the rod is bent the same amount.

OpenStudy (carolina4567):

If you bend a rod, say, 20 degrees, you will tend to compress one side and stretch the other. The compressed side is being forced to be a bit shorter than it wants to be, and the stretched side a bit longer. Now, double the thickness of the rod. The amount of compression on the compressed side is now double, and the amount of stretching on the other side is also doubled.

OpenStudy (faiqraees):

That's a copy pasted answer of yahoo.(Which was ofcourse myy first choice)

OpenStudy (faiqraees):

But still it doesnt addresses the question correctly. The question asks why the thin wire can BEND more without BREAKING?

OpenStudy (mimi1599):

So is it wire or rod

OpenStudy (faiqraees):

@vishweshshrimali5

OpenStudy (bobo-i-bo):

I think that @carolina4567 's answer does answer the question. I think it boils down to the fact that the outside of the thicker rod goes through more strain for the same amount of bending, therefore, it seems obvious that the outside of the thicker rod is going to break first (and hence the thicker rod will bend less before it breaks).

OpenStudy (faiqraees):

@Bobo-i-bo I want to ask how the difference in the extension at the inner and outer sides and can result in breaking of the object?

OpenStudy (faiqraees):

@reemii

OpenStudy (reemii):

maybe because of the "stretch" on the outer part. |dw:1460998044872:dw| When you bend, the rod becomes an arc of a circle. With a big rod, the outer part is further away from the center of that circle and therefore stretches more.|dw:1460998137524:dw|

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