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OpenStudy (sweetnikkie072):
7
Directrix (directrix):
@sweetnikkie072 How did you get 7? Please show some work. Thanks.
OpenStudy (logan13):
7.5
jhonyy9 (jhonyy9):
7*7=49*7=343
OpenStudy (sweetnikkie072):
okhay..so basically you are finding cubic root of 343..honestly i just remember some basic square roots and cubic roots..what you can do is use long division too..is that what you want me to explain?
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OpenStudy (sweetnikkie072):
its basically how you multiply numbers 3 times which gives you the answer..if you look at it
OpenStudy (agent0smith):
Remember learning prime factorization?
|dw:1461012062330:dw|
So 343 = 7*7*7 = 7^3
OpenStudy (logan13):
so 73
OpenStudy (agent0smith):
7*7*7 is not 73. Neither is 7^3. 7^3 is\[\Large 7^3\]
OpenStudy (agent0smith):
\[\Large \sqrt[3]{343} = \sqrt[3]{7^3} =?\]
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OpenStudy (logan13):
so its
OpenStudy (agent0smith):
So it's...?
OpenStudy (logan13):
idk
OpenStudy (agent0smith):
Here's a hint\[\Large \sqrt[n]{x^n} = x\]
OpenStudy (logan13):
so would it be 3
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OpenStudy (logan13):
@agent0smith -3
OpenStudy (agent0smith):
Look at the hint more carefully
OpenStudy (logan13):
55.5607775324
OpenStudy (logan13):
so 55
OpenStudy (sweetnikkie072):
7*7*7..so you are multiplying 7 ...three times....and you are getting 343...now my question to you is.....what is the number that you multiply 3 times to get 343?....
7?
so what is the cubic root ( 3√) of 343?
7?
therefore...
3√(343)=7
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