Question

Solve x^2 = 121.

60.5
−11
11
±11

Answer 1

@surjithayer

Answer 2

\[x^2-121=0,x^2-11^2=0 \]
\[a^2-b^2=\left( a+b \right)\left( a-b \right)\]

Answer 3

b? -11?

Answer 4

No but close

Answer 5

Try again

Answer 6

11 c?

Answer 7

\[x^2 - 11^2 = (x+11)(x-11)\]

Answer 8

hint : it has something to do with a 11

Answer 9

Or you can think of it like this:
\[x^2 =121\]
\[x=\pm \sqrt{11}\]

Answer 10

D/

Answer 11

yes correct

Answer 12

Because 11*11 = 121, and -11*-11 also equals 121.

Answer 13

ok! :)