Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.
Did you try to use the formula$$(x-h)^2 = 4p(y-k)$$
I have the formula written down but I'm struggling to apply it
|p| is the distance between the focus and the vertex , or the distance between the directrix and the vertex.
How would I find the vertex?
the vertex is halfway between the focus and the directrix https://www.desmos.com/calculator/rr6bgwsu6k
So vertex = (0,0)
And p = 2
yes, very close. except p is negative because it opens downwards.
Oh okay. So x^2 = 4(-2)(y)
bingo :) And you can graph that on desmos.com https://www.desmos.com/calculator/ljgyaybts9
Thank you for all your help, I understand this a lot better now.
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