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Mathematics 17 Online
OpenStudy (alexh107):

Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.

OpenStudy (perl):

Did you try to use the formula$$(x-h)^2 = 4p(y-k)$$

OpenStudy (alexh107):

I have the formula written down but I'm struggling to apply it

OpenStudy (perl):

|p| is the distance between the focus and the vertex , or the distance between the directrix and the vertex.

OpenStudy (alexh107):

How would I find the vertex?

OpenStudy (perl):

the vertex is halfway between the focus and the directrix https://www.desmos.com/calculator/rr6bgwsu6k

OpenStudy (alexh107):

So vertex = (0,0)

OpenStudy (alexh107):

And p = 2

OpenStudy (perl):

yes, very close. except p is negative because it opens downwards.

OpenStudy (alexh107):

Oh okay. So x^2 = 4(-2)(y)

OpenStudy (perl):

bingo :) And you can graph that on desmos.com https://www.desmos.com/calculator/ljgyaybts9

OpenStudy (alexh107):

Thank you for all your help, I understand this a lot better now.

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