A bag contains 7 green marbles, 9 red marbles, 10 orange marbles, 5 brown marbles, and 10 blue marbles. You choose a marble, replace it, and choose again. Find P(green, then blue). If you answer this question I will no longer have any questions because this will help me with anything! Please help!
@mathmale ...?
Hi! Okay, so the key part of this is that it says you REPLACE the marble. This means that the total number of marbles never changes.
First you have to find the fractions that represent the chance of picking a green marble, and then a blue marble
Then, multiply those fractions together to get your answer.
Ok so that means this problem has something to do with experimental probability?
yeah ! can you figure out the answer?
yes, so total marbles = 41 so the fractions would be 7/41 and 10/41?
exactly :] now multiply those together
Ok! so the answer is 70/41?
Not quite. You multiply fractions differently than that, give me 1 sec
My calculator is saying 84/1681 but that seems like a really odd fraction to have as an answer
oh.. so are you supposed to just multiply straight across like 7 * 10 and 41 times 41?
sorry that took so long my computer is being slow
yes, that's how you do it
ok thankyou so much! (and I like your profile picture btw :P)
haha thanks ! i drew it myself
really? :O thats amazin!
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