I understand what direct variation is but now I need help solving a different question and im confused again... Which equations show a direct variation between x and y when solved for y? Choose all answers that are correct. A. y-9=2x+9 B. y=4/7x C. 4+y=1/3x+4 D. y=3/x
@jim_thompson5910
let's focus on y-9=2x+9 for now
how would you isolate y?
+9 and cancel it out?
yes add 9 to both sides
y-9=2x+9 y-9+9=2x+9+9 y = 2x + 18
so y=2x+18
oh you already put it lol
that's ok. So is y = 2x+18 in the form y = k*x ?
I think if there's no 18, then yes
so because of that added 18, it means it's not in direct variation form
So A can't be one of the answers
agreed
if choice B is \[\Large y = \frac{4}{7}x\] then is it in y = k*x form?
Yes
good, so k = 4/7 in this case
And for C, i'll try to do the same thing we did for A.
yes
what do you get?
Cancel out the 4 on both sides and you get y=1/3x which is in the form of y=k*x, right?
yep k = 1/3 here
So what about D?
D is in the form y = k/x where k = 3 in this case. This is inverse variation (not direct variation)
Oh like the other one we did earlier, so D isn't an option... so the answers are A and C
*B and C
yes B and C are the two answers
so the next question is asking for the constant of variation, how do I find that?
it's the value being multiplied by the x example: y = 3x has a constant of variation of k = 3
There's a table involved... https://static.k12.com/calms_media/media/240500_241000/240875/1/84c7a8e958278f581d334091e36c5623014c9a18/01_09_LQ_2.gif
focus on the column with x = 1 and y = 3 y = k*x 3 = k*1 ... replace x with 1 and y with 3 solve for k
1?
3 is equal to SOMETHING times 1 what is that SOMETHING?
1/3?
3 = k*1 so k = 3
k = 3 is the constant of variation
Ohh It's 3 for the rest of them too if you solve them the same way
yeah notice how if x = 2 then y = 6. You'd get the same value of k
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