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Mathematics 24 Online
OpenStudy (erikaxx):

..

jimthompson5910 (jim_thompson5910):

all parabolas that have the axis of symmetry along the x axis look like this 4p(x-h) = (y-k)^2

jimthompson5910 (jim_thompson5910):

(h,k) is the vertex |p| = distance from vertex to focus

OpenStudy (erikaxx):

parabola formula is (y-k)^2 = +/- 4a ( x-h ) if it is going right or left and (x-h)^2 = +/- 4a (y-k) if it is up or downward

OpenStudy (erikaxx):

thats the given formula that i write above

jimthompson5910 (jim_thompson5910):

focus F is at the point (h+p,k) since we're told that F is at the origin, this means (h+p,k) = (0,0) h+p = 0 k = 0

OpenStudy (erikaxx):

please use the fomula i wrote

jimthompson5910 (jim_thompson5910):

ok so instead of 'p', use 'a'

OpenStudy (erikaxx):

yes, so before we solve it, we need to identify it it is right/left or up/downward

OpenStudy (erikaxx):

what is our graph?

jimthompson5910 (jim_thompson5910):

|dw:1461394156685:dw|

jimthompson5910 (jim_thompson5910):

the parabola looks like this |dw:1461394172236:dw|

OpenStudy (erikaxx):

why it looks like that the graph

jimthompson5910 (jim_thompson5910):

or like this |dw:1461394190679:dw|

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