Easy medals:
This question is about parabolas. Click for more details

Question

Easy medals:
This question is about parabolas. Click for more details

aimatias · Answer

attachment

aimatias · Answer

@Owlcoffee  do you think you can help me solve this?

latinc · Answer

first hint, the first term has to be positive

owlcoffee · Answer

given the equation of a generic parabola:
$$y=ax^2 + bx + c $$
The concavity or the "opening" of the parabola is determined by the coefficient "a" so if it is positive it opens upwards, if it's negative, it opens downwards.
The position of the vertex is determined by the following form:
$$V \left( \frac{ -b }{ 2a } , \frac{ 4ac-b^2 }{ 4a }\right)$$

owlcoffee · Answer

I wrote a tutorial involving the discussion and derivation of the equations involving a parabola: http://openstudy.com/users/owlcoffee#/updates/570c9603e4b0df36b96a4636

owlcoffee · Answer

The equation: $$y=ax^2+bx+c$$
represents a parabola parallel to the y-axis, therefore the positioning of the vertex will be determined by the terms "bx+c".
I personally find more useful to calculate the vertex instead of "observing" it on the equation.

aimatias · Answer

thank you