Question

Any idea

Answer 1

What did u need help with?

Answer 2

@king2001

Answer 3

The problem is in the photo

Answer 4

what photo theres no photo

Answer 5

\[\Huge\color{#3debf5}{\mathbb{WELCOME\\TO\\OPENSTUDY}}\]\[\small\color{black}{I'm~sorry,~there~is~no~picture~attached~to~this~question.\\If~you~would~like~to~ask~a~question,~please~post~a~picture~or~the~question~it's~self.\\Thanks!}\]

Answer 6

Starting from 130 feet away, a person on bicycle rides toward a checkpoint and then passes it. The rider is traveling at a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|at what times is the bike 15 feet away from the check point

Answer 7

well you have to replace d with 15 because the distance is 15 feet away

Answer 8

so you have \[15=130-25t\]
do you know how to simplify that?

Answer 9

4.6 sec and 9.2 sec
2.9 sec and 5.8 sec
4.6 sec and 5.8 sec
2.9 sec and 3.3 sec

Answer 10

do you know how to simplify that equation?

Answer 11

Rhonda's question is appropriate: 15=130-25t need to be simplified first, and then solved for the value of the variable t that satisfies the equation.

15 and 130 are "like" terms; how would you combine them into ONE term?

Answer 12

23/5?

Answer 13

Was that meant to be the result of combining 15 and 130? Your 23/5 shows division, where no division is called for.

Note that the 15 and the 130 are on opposite sides of the = sign. You need to move the 130 to the left side of this equation. To accomplish this, subtract 130 from both sides of the equation 15=130-25t.

Answer 14

not quite. I would try subtracting 130 from both sides. it is the simplest way to get the coeeficient of (t) and (t) itself to one side
\[~~~~~15=~~130-25t\]\[-130~~~-130\]\[---------\]\[~~~~~~~?~~~~~~~~~~~?-25t\]

Answer 15

115=-25

Answer 16

Idk

Answer 17

15-130=-145
-145=-25t
you then have to divide -145 by -25 to get t by its self

Answer 18

so divide -145 by -25