Question

General form

Answer 1

\[\frac{ 1 }{ 4 } x^2 +5=0\]
Give the values of a, b, and c needed to write the equation's general form.

Answer 2

?

Answer 3

Compare your \[\frac{ 1 }{ 4 } x^2 +5=0\]

Answer 4

to the general form of a quadratic equation: By comparing these two quadratics, you should be able to read off the values of a, b and c immediately.

Answer 5

Hint: think of the given equation as (1/4)x^2 + 0x + 5 = 0

Answer 6

What he said ^
\(\frac{1}{4}x^2 + 0x + 5 = 0\)
\(ax^2 + bx + c = 0\)

Answer 7

Uhh i know this formula

Answer 8

okay. so the standard form of quadratic is \(ax^2 + bx + c = 0\) where a and b are coefficients and c is a constant.

so in \(\frac{1}{4}x^2 + 5 = 0\), you can pretend that there is a 0x. if there is a 0x then it just means that it acts as like a "place holder" for the b term and it has no major effect on the value of the quadratic.

now we have:
\(\frac{1}{4}x^2 + 0x + 5 = 0\)

can you name the a, b , and c terms based on the standard form (or general form) of the quadratic equation?

Answer 9

my formula A = 1; B = 0; C = -5

Answer 10

that's not exactly correct. only the b term is correct. @AloneS

Answer 11

here is an example.

if i needed to identify the a, b, and c terms in the following quadratic: \(2x^2 + 0x + 8 = 0\), then the a = 2, b = 0, c = 8.

Answer 12

Oh i think i got it A = 1; B = 0; C = 20

Answer 13

not quite. i am unsure where u are getting a=1 and c=20.

you should be actually getting a=1/4 and c=5
that is what is given