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50 cc of antifreeze (ethylene glycol), C2H6O2, d=1.22 g/cc, is mixed with 50 g water. What is the freezing point of this “50-50” solution? (Kf=1.86 C/m)
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@Nnesha
ΔT=Kf m m= molality you have to calculate the molality (number of moles of solute per kilogram of solvent) of C2H6O2 in your solution and multiply by the Kf to find the ΔT. the freezing point of the solution will be 0-ΔT =???
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