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Mathematics 15 Online
OpenStudy (deercult):

What is the area of the shaded region in the given circle in terms of pi and in the simplest form?

OpenStudy (deercult):

OpenStudy (abdullahm):

We have to find the area of the sector and subtract it by the area of the equilateral triangle. That way we find the area of the unshaded region. We then find the area of the circle and subtract the area of the unshaded region from it to get your final answer. Ready to begin?

OpenStudy (deercult):

Ok! Yep! I'll do my best to follow along!

OpenStudy (abdullahm):

To find the area of the sector: \(\Large\bf Area =\frac{n}{360}\pi r^2\) where n is the angle. In our case n is going to be 60. So plug it in and find the area of the sector. Area of a sector basically means the area of a slice of the circle.

OpenStudy (deercult):

\[\frac{ 60 }{ 360 }\pi6^{2}\] Is this the right equation? If so, then you'd get, \[0.2\pi36 \] Which ends w/ 22.6 Is that right?

OpenStudy (abdullahm):

Well \(\Large\frac{1}{6}(6^2) \pi\) \(\Large =6\pi\approx 18.85\)

OpenStudy (abdullahm):

Now to find the area of an equilateral triangle, we can use this formula: \(\Large\bf Area = \frac{\sqrt{3}}{4}a^2\) where a is the side of the triangle In our case a = 6

OpenStudy (deercult):

Ohh. Alright, one second!

OpenStudy (deercult):

Is it 15.6?

OpenStudy (deercult):

Or 15.59

OpenStudy (abdullahm):

Let's go with 15.59 since that's more accurate!

OpenStudy (abdullahm):

Now, what is 18.85 - 15.59 = ?

OpenStudy (deercult):

Ok! I got 3.26!

OpenStudy (abdullahm):

Correct! Now we need to find the area of the circle \(\Large\bf Area = \pi r^2\) where r is the radius, and r is 6 in our case. What is the area?

OpenStudy (deercult):

\[36\pi\] Or 113.04

OpenStudy (abdullahm):

and then subtract 3.26 from that!

OpenStudy (abdullahm):

113.04 - 3.26 = ?

OpenStudy (deercult):

109.78!

OpenStudy (abdullahm):

That's your final answer!

OpenStudy (deercult):

Ok! One thing, the answers are all in this format: http://prntscr.com/b0qn0o

OpenStudy (deercult):

Sorry D: I only juts noticed

OpenStudy (abdullahm):

Oh, they wanted an exact answer. So let's just put all of our work together in the exact answers. \(\Large\bf 36\pi - (6\pi - 9\sqrt{3})\) That's basically what we did. And if we simplify that, we get: \(\Large\bf 36\pi - 6\pi + 9\sqrt{3}\) which is the same thing as \(\Large\bf 30\pi + 9\sqrt{3}\) Do you understand? \(\ddot\smile\)

OpenStudy (deercult):

Ah, yeah, I understand! Thanks a ton!

OpenStudy (deercult):

Thank you so much!!!

OpenStudy (abdullahm):

It was my pleasure!

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