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OpenStudy (stbest):
Plz explain how to do this ASAP
OpenStudy (stbest):
@kittiwitti1
OpenStudy (kittiwitti1):
Sorry, I've got to study for my 10-chapter final exam ^-^;
OpenStudy (stbest):
k
OpenStudy (stbest):
Good Luck
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563blackghost (563blackghost):
What exactly are you trying to find?
OpenStudy (stbest):
What arc MRT is
563blackghost (563blackghost):
Are there options to this?
OpenStudy (stbest):
no
OpenStudy (stbest):
i know the formula and everything except IDK how much degrees mrt is
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OpenStudy (stbest):
\[l=(\frac{ mrt }{ 360 })2PIr\]
and the radius is 5
563blackghost (563blackghost):
If we are going to mrt as x we need to know what l is....
OpenStudy (stbest):
\[l=(\frac{ mrt }{ 360})10PI\]
OpenStudy (stbest):
but how do i find the length if to find it i need mrt
563blackghost (563blackghost):
One sec Im looking through my formulas because i dont really recognize yours...
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OpenStudy (stbest):
k
563blackghost (563blackghost):
I think we use formula....
\(\Huge{m \angle 1=\frac{1}{2} (x-y)}\)
Where MRT would be x and 50 would be y and 35 would be \(\large{m \angle 1}\)...
\(\Huge{35=\frac{1}{2}(x-50) \rightarrow 70=x-50}\)
In which we would add....
\(\Huge{70+50=x=120}\)
So Arc MRT would be 120 degrees.
OpenStudy (stbest):
WOW THANKS
563blackghost (563blackghost):
np ^^
OpenStudy (stbest):
im gonna copy the formula
:D
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563blackghost (563blackghost):
I'll send you a pic one sec
OpenStudy (stbest):
k
563blackghost (563blackghost):
Here you go ^^
OpenStudy (stbest):
Thanks
OpenStudy (stbest):
K the quiestion is closed
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