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Mathematics 19 Online
OpenStudy (burak00b):

please help Draw a point on the y-axis such that the slope of a line between that point and the red dot is −0.5 It is OK just to write the coordinates rather than physically draw the dot. Hint: You can solve this either with algebra or with iteration.

OpenStudy (burak00b):

OpenStudy (itsmerobbie):

http://www.bvog.com/?post=IDhU5xU0kf24NcqvZ

OpenStudy (burak00b):

thanks for your help, but the link isn't working :)

Directrix (directrix):

> It is OK just to write the coordinates Instructions are this: Draw a point on the y-axis Do you have the coordinates of the point? @Burak00B

OpenStudy (burak00b):

@Directrix yes, the coordinates of the point are (6,-2) and m= -0.5

Directrix (directrix):

Have you calculated the point on the y-axis that with (6,-2) has a slope of -.5?

Directrix (directrix):

The task is to find two points with a slope of -.5 given that one point is (6,-2) and the second is (0,y) which is a point on the y-axis.

OpenStudy (burak00b):

@Directrix I did this : point(6,-2) m=-.5 y=mx+b -2=(-.5)(6)+b b= 1

Directrix (directrix):

Okay, I got (0.6) as the point on the y-axis.

OpenStudy (burak00b):

i got b=1 please correct me if I'm wrong y=mx+b -2=(-0.5)(6)+b -2=-3+b b= -2+3 b=1

Directrix (directrix):

Then, locate the calculated point on the graph.

OpenStudy (burak00b):

yes so I located the (0,1) point on the graph just like your graph

OpenStudy (burak00b):

do I have to connect the lines on the graph or just leave it like this

Directrix (directrix):

I used the slope formula. - 1/2 = (y + 2) / (0-6) That cranks out to a y value of 1.

OpenStudy (burak00b):

oh so its the same answer then :)

Directrix (directrix):

The instructions say to draw the point. So, that is what I would do. I would include the work on how I calculated the coordinates of the point.

OpenStudy (burak00b):

ok yes I will write down the steps next to the graph as well

OpenStudy (burak00b):

thank you so much for your amazing help, really appreciate it thank you :)

Directrix (directrix):

You are welcome.

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