Factor the following expression . 16v^8 x^9 -28v^2x^6y^3
@Photon336
do i take the highest exponent or lowest ?
The lowest
when do i ever take the highest exponent ?
\[16v^8 x^9 -28v^2x^6y^3\] \[\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba\] \[x^9=x^6x^3,\:v^8=v^2v^6\] \[=16x^6x^3v^2v^6-28y^3x^6v^2\] \[\mathrm{Factor\:out\:common\:term\:}4v^2x^6\] \[=4v^2x^6\left(4v^6x^3-7y^3\right)\]
@Eunice_O are you understand
Hello :D I can help you go through it step by step. would you like that?
yes
okay great. :D give me one second...(i want to solve it so im sure you dont mess up)
\[What~is~the~largest~number~that~divides~evenly~into~16v^8x^9 and −28v^2x^6y^3?\]
4?
yep :D
but how do i know when to take the highest exponent ?
\[What~is~the~highest~degree~of~v~that~divides~evenly~into\\16v^8x^9~and~−28v^2x^6y^3\]
v^8?
not quite... what is the smallest exponent, 2? or 8?
2? but u asked me the highest degree
that will divide evenly with both of them
you couldnt divide 8 out of the other one because it only had 2
okay but can you please help me with this other question i really do not understand it . Please :)?
._. do you fully get this one?
yes
post it as a new question
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