A 3,500 kg truck accelerates uniformly from 15.00 m/s to 35.00 m/s east. During this acceleration, the track travels 187 m. What is the net force acting on the car during this acceleration.

Question

maths99 · Answer

Calculate the trucks acceleration then plug that into F=ma.

g3n3sis08 · Answer

Correct me if I'm wrong.

a=(v-u)/t
35-15/t = 20/t
s=ut + 1/2 at^2
187=(15)t+(0.5x(20/t)xt^2)
187=15t + 10t
187/25=t

a=20/t ... (20x25)/187=a
F=ma
F=(3500x20x25)/187
F=9358.3 N
therefore,
F is approx. 9360 N